)WORD COUNT TYPE ; IMMEDIATE This works fine when used in a line like: .(
5. but consider what happens if the user enters an empty string: .(
5. The definition of .( shown above would treat the
)as a leading delimiter, skip it, and continue consuming characters until it located another
)that followed a non-
)character, or until the parse area was empty. In the example shown, the
5. would be treated as part of the string to be printed. With PARSE, we could write a correct definition of .(: : .( [CHAR]
)PARSE TYPE ; IMMEDIATE This definition avoids the "empty string" anomaly.